We can model these phenomena by the equation dy/dt = ky where:
y(t) is the value of the quantity at time t,
k is a constant,
dy/dt is a rate of change of y with respect to t.
If k > 0, then dy/dt > 0 is the GROWTH rate.
If k < 0, then dy/dt < 0 is the DECAY rate.
The above equation is a differential equation because it involves an unknown function y and its derivative dy/dt. The solutions of the differential equation dy/dt = ky are y(t) = y(0).exp(kt) where y(0) is the initial value.

In exponential growth (k > 0), the rate of change increases over time - the rate of the growth becomes faster as time passes. In exponential decay (k < 0), the rate of change decreases over time - the rate of the decay becomes slower as time passes.
Depending on your major or area of interest, please choose ONE example in Section 3.8 of the textbook and answer the following questions:
1) Specify the number of the example you chose (example 1, example 2, etc).
2) In this example, please analyze how the above model is used.
3) Is your chosen example exponential growth or decay?
If you do not have the textbook, you can look at the examples of Section 3.8 on the class website.
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